Maximize 2 32 6 20 Subject To 1 A 6 30 Lt 30 2 2 2 26 50 Lt 24 3 42 6 20 Lt 36 4

Maximize z = 3a + b + 2c and the rest is on the picture

Maximize 2 = 32 + 6 + 20Subject to :"1 .a + 6 + 30 < 302 .2 2 + 26 + 50 < 243 .42 + 6 + 20 < 364 .2 , 6 , ( 2 0NB : a = Computers 6 = Network devices c = IP camerasZ = Performance- Numbers are costs .The problem above consist of maximizing the performance of our computer network by reducing*the total cost .

 

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