In A Random Sample Of 50 Refrigerators The Mean Repair Cost Was 146 00 And The P
In a random sample of 50 refrigerators, the mean repair cost was
$146.00
and the population standard deviation is $17.80
.
Construct a 90% confidence interval for the population mean repair cost. Interpret the results.
Construct a 90% confidence interval for the population mean repair cost.
The 90% confidence interval is ( ? , ? )
(Round to two decimal places as needed.)
I
nterpret you results. Choose the correct answer below.
A.With 90% confidence, it can be said that the confidence interval contains the true mean repair cost.
B.With 90% confidence, it can be said that the confidence interval contains the sample mean repair cost.
C.The confidence interval contains 90% of the mean repair costs.
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