If My Initial Rate Is 2e05 Mol L When I Insert This Value Into To Rate Law R K

If my initial rate is -2E05 mol/L , when I insert this value into to rate law R=k[0.048][0.048]  and solve for K will my be a negative value.  I am not sure if I am suppose to remove the negative sign from -2E05? Subject is general chemistry II

 

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