How Do I Find The Directrix Of The Parabola Y 2x 2

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To find the directrix of a parabola wohse equation is ##y=ax^2+bx+c## you can use this formula:##y= (-1-(b^2-4ac))/(4a)##So in case of this parbola ##y=2x^2##the directrix is##y=(-1-(0^2-4*2*0))/(4*2)####y=-(1)/(8)##

 
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