1 The Base Of Machine Is Supported By Four 4 Two 2 Leg Supports Like A Shipping Cont 3951371

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1. The base of machine is supported by four (4) two (2) leg supports (like a shipping container crane) consisting of 2.4m long steel struts pinned at each end. The machine must remain level and aligned at all times. Due to a maintenance issue, one of the 20mm square struts is replaced with a 20mmx50mm titanium one.

1a. What is the result of this on pin “C”

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2. A 500ft length of 3/4”-6×37 class bright wire rope EIPS IWRC (steel cable) is to be used to suspend some lights across a football field. It is attached to adjustable eye bolts at each support. Each eye bolt has 12 inches of adjustment available. The bolts are exactly 500 ft apart to start.

2a. How far do you need to loosen the eye bolts to initially hang just the cable? (Note: it may help to treat the distributed load as a point load at the middle with the cable acting as two thin rods initially 250 ft long)

2b. What is the final position of the bolts in order to have the cable “sag” less than or equal to 6 inches after the light) is attached?

Note Hibbeler Mechanics of Materials 10th Edition R3-4 and R3-5 may help you. Attached.

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3. A steel process component is mad by welding three (3) pipes to two (2) pre drilled steel end plates. Due to a serious lack of caffeine, the center pipe is cut 0.35mm short. The worker decides to fix the problem by forcing the ends together in a large vice and then welding the center pipe (B).

3a. What is the stress in each pipe after it is removed from the vice? (Neglect any welding stress)

Note that triangle thing (all connections) on C is a welding symbol for a 6mm fillet.

3b. Discuss/explain what this did to the capacity of the finished part.

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© 2017 Pearson Education, Inc., Hoboken, NJ. All rights reserved. This material is protected under all copyright laws as they currently exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher. *R3–4.1The wires each have a diameter of in., length of 2D2 ft, and are made from 304 stainless steel. If P = 6 kip, Cdetermine the angle of tilt of the rigid beam AB.2 ftP2 ft 1 ftBASolutionEquations of Equilibrium: Referring to the free-body diagram of beam AB shown in Fig. a,+S M = 0; F (3) – 6(2) = 0 F = 4 kipA BC BC+ cSM = 0; 6(1) – F (3) = 0 F = 2 kipB AD ADNormal Stress and Strain:3F 4(10 )BCs = = = 20.37 ksiBC2Ap 1BCa b4 23F 2(10 )ADs = = = 10.19 ksiAD2AAD p 1a b4 2Since s 6 s and s 6 s , Hooke’s Law can be applied.BC Y A Y3 -3s = EP ; 20.37 = 28.0(10 )P P = 0.7276(10 ) in.>in.BC BC BC BC3 -3s = EP ; 10.19 = 28.0(10 )P P = 0.3638(10 ) in.>in.AD AD AD ADThus, the elongation of cables BC and AD are given by-3d = P L = 0.7276(10 )(24) = 0.017462 in.BC BC BC-3d = P L = 0.3638(10 )(24) = 0.008731 in.AD AD ADReferring to the geometry shown in Fig. b and using small angle analysis,d – d0.017462 – 0.008731 180°BC AD-3u = = = 0.2425(10 ) rad a b = 0.0139° Ans.36 36 p radAns:u = 0.0139°177This work is protected by United States copyright laws and is provided solely for the use of instructors in teaching their courses and assessing student learning. Dissemination or sale of any part of this work (including on the World Wide Web) will destroy the integrity of the work and is not permitted.© 2017 Pearson Education, Inc., Hoboken, NJ. All rights reserved. This material is protected under all copyright laws as they currently exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher. R3–5.1The wires each have a diameter of in., length of 2D2 ft,…

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1 The Midnight Hour A Local Nightclub Earned 100 000 In Accounting Profit Last Year 1040006

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1)The Midnight hour, a localnightclub, earned $100,000 inaccounting profit last year. Thisyear the owner, who had invested $ 1million in the club, decided toclose the club. What can you sayabout economic profit (and the rateof return)in the nightclub business?ANSWER:Economic Profit = TR(total revenue)-TC(total economic cost)EP = $100,000 – $1,000,000EP = -$900,000Since EP is a negative number thefirm should shut down, the output isnot positive, therefore the companyoperates at a loss, the managerneeds to determine how long theywant to continue with this lossprocess.Does this sound like the correctanswer?Thanks,EY

 
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1 The Aerodynamic Drag On A Vehicle Is Thought To Depend On The Following Properties 2803253

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1. The aerodynamic drag on a vehicle is thought to depend on the following properties: ? Density of the fluid ? Viscosity of the fluid ? A representative length scale of the vehicle. ? Flow velocity

 
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1 The Gamma Corp Has Decided To Enter The Next Generation In Customer Service In Ord 2838656

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1) The GAMMA Corp. has decided to enter the next generation in customer service. In order to do so they need to purchase a new piece of equipment. The equipment is highly specialized and needs to be created to exact specifications. As a result it will take at least 30 months for the equipment to be ready for installation and will cost a total of $270,000. GAMMA Corp. wants to set aside the money it needs for the equipment today. Being extremely conservative the company will be placing the funds it needs for the purchase into a GIC with a rate of 2.1% compounded Semi-Annually.

A- How much money are they setting aside today?

B- What would the interest rate be if they only needed to save $221,920.32 at the beginning? (Input as a percentage without the % sign)(Remember (-) where appropriate)

C -How much would they need if they had more time to allow money to grow such as if the equipment would be ready in 5.5 Years at a rate of 2.1% Compounded Semi-Annually?

2) Jane is an analyst and their company wants to get a return of atleast 4.4% compounded Quarterly on their investment. Jane will only have use of the money for 12 Months before the company needs it for another project. Jane has been give $1,200 to invest.

A- If Jane is able to find an investment matching the criteria, how much money will they have after 12 Months?

B- If the rate of return ended up being 11.5% and the company invested their $1,200. How much would they have after 12 Months?

C- The company liked the 11.5% and decided to leave the money invest until they earned 6,573.13. How long was the money actually invested for in MONTHS? (REMEMBER (-) signs where appropriate).

 
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1 The Balances In The Perpetual Inventory Accounts Of Valley View Manufacturing Corp 2633267

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1. The balances in the perpetual inventory accounts of Valley view Manufacturing Corporation at the beginning and end of the current year are as follows:

End of Year

Beginning of Year

Inventory accounts:

Materials . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

$15,000

$25,000

Work in Process . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

10,000

8,000

Finished Goods Inventory . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

24,000

30,000

Total dollar amounts debited and credited during the year to the accounts used in recording manufacturing activities are as follows:

Debit Entries

Credit Entries

Account:

Materials Inventory . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

$225,000

$ ?

Direct Labour . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

200,000

210,000

Manufacturing Overhead . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

420,000

420,000

Work in Process Inventory . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

?

?

Finished Goods Inventory . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

?

?

Instructions

  1. Using these data, state or compute for the year the following amounts:
    1. Direct materials purchased.
    2. Direct materials used.
    3. Payments of direct labour payrolls.
    4. Direct labour cost assigned to production.
    5. The overhead assigned to production stated as a percentage of direct labour costs.
    6. Total manufacturing costs charged to the Work in Process Inventory account during the year.
    7. The cost of finished goods manufactured.
    8. The cost of goods sold.
 
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1 The Hawaiian Corporation Expects This Year S Net Income To Be 12 Million The Firm 2774505

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1) The Hawaiian Corporation expects this year’s net income to be $12 million. The firm’s target debt/assets ratio is 30 percent. This year, Hawaiian has $20 million profitable investment opportunities. According to the residual dividend policy, what should be Hawaiian’s dividend payout ratio this year?

 
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1 Telephone Operators And Receptionists Who Prevent Contacts To Deciders Are Classif 2846909

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1.Telephone operators and receptionists who prevent contacts to deciders are classified as A. initiators B.influencers C. buyers D.gatekeepers 2. Supplier?s goal is to enlarge their share of purchasing over time, it is a characteristic of buying situation and called as A.supplier’s rebuy B.purpose buying C.straight rebuy D.turned rebuy 3. A company’s buying products such as chemicals or steel from specialized hubs are classified as A.Horizontal markets B.vertical markets C.auction markets D.private markets 4.All individuals and groups participants that make purchasing decision and share common goals and risks are classified as A. supplier center B. buying center C. evaluation center D. initial awareness stage 5. Traditional supply situation in which focus is on competition rather than cooperation is classified as A.customer supply B.contract supply C.cooperation supply D.bare buying

 
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1 The Function Of The Rules Of Inference Is To Justify The Steps Of A Proof A True B 2861969

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1. The function of the rules of inference is to justify the steps of a proof. A) True B) False 2. A proof is a sequence of steps in which each step is either a premise or follows from earlier steps in the sequence according to the rules of inference. A) True B) False 3. Implication rules can be validly applied to part of a line. A) True B) False 4. According to the axiom of replacement, logically equivalent expressions may replace each other within the context of a proof. A) True B) False 5. Replacement rules are pairs of logically equivalent statement forms. A) True B) False 6. Conditional proof (CP) is a method that starts by assuming the negation of the required statement and then validly deriving a contradiction on a subsequent line. A) True B) False 7. Indirect proof (IP) is a method that starts by assuming the antecedent of a conditional statement on a separate line and then proceeds to validly derive the consequent on a separate line. A) True B) False 8. Invalid arguments cannot be proven as invalid using the methods of natural deduction. A) True B) False Document Preview:

Introduction to Formal Logic – Natural Deduction Examination – Spring 2014 Part I: True/False Instructions. Please circle ‘True ‘if the statement is true and ‘False’ if the statement is false. (2 pts each) 1. The function of the rules of inference is to justify the steps of a proof. A) TrueB) False 2. A proof is a sequence of steps in which each step is either a premise or follows from earlier steps in the sequence according to the rules of inference. A) TrueB) False 3. Implication rules can be validly applied to part of a line. A) TrueB) False 4. According to the axiom of replacement, logically equivalent expressions may replace each other within the context of a proof. A) TrueB) False 5. Replacement rules are pairs of logically equivalent statement forms. A) TrueB) False 6. Conditional proof (CP) is a method that starts by assuming the negation of the required statement and then validly deriving a contradiction on a subsequent line. A) TrueB) False 7. Indirect proof (IP) is a method that starts by assuming the antecedent of a conditional statement on a separate line and then proceeds to validly derive the consequent on a separate line. A) TrueB) False 8. Invalid arguments cannot be proven as invalid using the methods of natural deduction. A) TrueB) False 9. One of the rules of inference is DeMorgan’s theorem: ~(P v Q) :: (~P · ~ Q) A) TrueB) False 10. When an indirect proof is discharged, any lines derived from the assumption can no longer be used in the subsequent proof. A) TrueB) False Part II: Rules of Implication Instructions. Using the rules of implication, please provide the proofs for the following problems. Please provide justifications for each step. (7 pts each) 11. 1. T ? ( P v Q ) 2. S v ~ ( P v Q ) 3. ~S / ~ T 12. 1. ( S ? R ) · Q 2. R ? T / S ? T 13. 1. [ (…

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1 The Following Info Is Available Items Maturity Amount 1 A Chf Payable 1 Month 2 00 1545258

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1. The following info is available

ITEMS

MATURITY

AMOUNT

1. A CHF payable

1 month

2,000,000.

2. A CHF deposit

3 month

1,500,000.

3. A CHF receivable

1 month

500,000.

4. A CHF forward sale

6 month

450,000.

5. A CHF loan

6 month

1,000,000.

6. A CHF payable

9 months

850,000.

7. A CHF forward purchase

9 months

500,000.

8. A CHF loan

12 months

2,500,000.

Incase of a deposit or a loan, the amount is the maturity value which includes interest and the principal. The CHF interest rate is 6% for all maturities and is known to remain at this level with certainty.

You are required to work out a neat forex transaction plan for next one year to ensure smooth receipts and payments by the British company.

 
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1 The Traveling Salesman Problem Tsp Is A Famous Problem For Which There Is No Known 2835377

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1. The Traveling Salesman problem (TSP) is a famous problem for which there is no known,

tractable solution (though efficient, approximate solutions exist). Given a list of cities and the

distances in between, the task is to find the shortest possible tour (a closed walk in which all

edges are distinct) that visits each city exactly once.

Consider the following algorithm for solving the TSP:

n = number of cities

m = n x n matrix of distances between cities

min = (infinity)

for all possible tours, do:

find the length of the tour

if length

min = length

store tour

a) What is the worst-case (big-O) complexity of this algorithm in terms of n (number of

cities)? You may assume that matrix lookup is O(1), and that the body of the ifstatement

is also O(1). You need not count the if-statement or the for-loop conditional

(i.e., testing to see when the for-loop is done), or any of the initializations at the start of

the algorithm. Clearly show the justification for your answer.

b) Given your complexity analysis, assume that the time required for the algorithm to run

when n = 10 is 1 second. Calculate the time required for n = 20 and show your work.

2. Suppose an algorithm solves a problem of size x in at most the number of steps listed in each

question below. Calculate the asymptotic time complexity (big-T or big-theta) for each example

below. Show your work, including values for c and x0along the way.

a) T(x) = 1

b) T(x) = 5x – 2

c) T(x) =3x^3+ 2 + x2

d) T(x) = log (x * 2x!)

 
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