Question 2:

  1. Set up a frequency distribution table and calculate the relative frequency for the following quiz scores that Matt achieved in his Algebra course:
  2. Matt’s Quiz Scores: 87, 88, 92, 79, 100, 76, 61, 60, 79, 99, 100, 69, 98, 87, 92, 79, 81, 85, 100, and 100.
  3. Use the following frequency intervals:
  4. 60 – 69
  5. 70 – 79
  6. 80 – 89
  7. 90 – 100
  8. Calculate the variance and standard deviation for Matt’s quiz scores. Suggestion: set the problem up in steps within a table like the textbook illustrates.
 
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find the mass of a sphere of radius a if the density varies inversely as the square of the distance from the center.Ans: 4kaπ

779173431.12..2011find the mass of a sphere of radius a if the density varies inversely as the square of thedistance from the center.Ans: 4kaπShow calculationsAnswer: density varies…

 
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Find the margin of error for each sample. Round each margin of error to the nearest whole percent. Then find an interval that is likely to contain the true population proportion.18% of 350 students (3 points)±5%; 13% to 23%±5%; 23% to 33%±13%; 33% to 43%±5%; 33% to 43%

 
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Find the magnitude of the current density in a sample of silver for which conductivity equal to 6.17*10^7 S/m and mobility of electron is equal to 0.0056 m^2/v if 1)The sample is a cube 2.5 mm on a side having a voltage of 0.4mv between opposite faces 2)The sample is a cube 2.5 mm on a side carrying a total current of 0.5A.

 
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## f(5)=1/10## is a local max.## f(-5)=-1/10## is a local min.

##f(x)={x}/{x^2+25}##

By ,

##f'(x)={1 cdot(x^2+25)-x cdot 2x}/{(x^2+25)^2}={25-x^2}/{(x^2+25)^2}=0##

##=> x= pm5″ “## (Critical Numbers)

First Derivative Test

##{(f’:(-) to (+)” at “x=-5 => f(-5)=-1/10″ is a local min.”),(f’:(+) to (-)” at “x=5 => f(5)=1/10″ is a local max.”):}##

Second Derivative Test

By Quotient Rule,

##f”(x)={ -2x(x^2+25)^2-(25-x^2)cdot2(x^2+25)(2x)}/{(x^2+25)^4}={2x(x^2-75)}/(x^2+25)^3##

##{(f”(-5)>0 => f(-5)=-1/10″ is a local min.”),(f”(5)<0 => f(5)=1/10″ is a local max.”):}##

I hope that this was helpful.

 
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Can someone help me figure this out? I am confused…

Find the inverse of this matrix using the row operations tool: 1 2 16 1 00 0 6If M denotes the inverse, so that mhv is the entry of the inverse in row i and column j, give the following entries of M as fractions reduced to lowest terms.”11,1 =”11,3 = .m2,1 = _ ”13,3 =

 
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1.find the inverse of f(x)=4x2 for x >/ 0.

The inverse function is f-1(x)=

2.The monthly profit from producing and selling x units of a product is given by the formula below.

p(x)= – 0.2×2 + 500x – 200,000

producing and selling how many units will result in a profit for this product?

use an interval to describe how many units can be produced and sold to produce a profit.

3.The total revenue function for a certain product is given by R=560x dollars, and the total cost function for this product is C= 20,000 + 40x + x2 dollars, where x is the number of units of the product that are produced and sold.

a. find the profit function.

b.find the number of units that gives maximum profit.

c. Find the maximum possible profit.

a. P(x) =

b. Th number of units that gives maximum profit is x =

c.The maximum possible profit is $

4.if f(x) = x2 – 4x and g(x) = 9 – x3 , evaluate the fallowing.

a.(f+g)(1) =

b.(g – f) (3) =

c.(f * g)(-1)=

d.(g/f) (-3) =

 
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can I please get help with these questions.i tried it but I keep getting the wrong answers.i will greatly appreciate it.

pls don’t flag

Find the inverse for the following functions. If it does not exist, show why. — f(x) = 2x— 1‘ “1): The values of g and g ‘ are given in Table 6. Complete Ihe columns for 3-1 and ( g _1 ) ‘ . 3- [40 ml Find the derivativeIn x war-(x1)And the integral 6::I9+x4 d3:

 
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Find the net torque on the wheel in the figure below about the axle through O perpendicular to the page, taking a = 15.0 cm and b = 29.0 cm. (Indicate the direction with the sign of your answer. Assume that the positive direction is counterclockwise.) Answer= __________N m

 
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Find the net force on the moon (Mm 7.35×10^22) due to the gravity attraction of both Earth (Me= 5.98×10^24) and the sun (Mg= 1.99×10^30) assuming they are at right triangles to each other Earth is 3.84×10^5km from the moon.

 
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