MET CS CS625 Business Data Communications and Networks

Lab 5 Submission

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This submission template is a convenient document for you to provide your

work and your answers for Lab 5. This submission template is intended to

be used in conjunction with the Lab 5 Instructions document. The

instructions document illustrates how to correctly derive the answers,

explains important theoretical and practical details, and contains the

complete set of instructions for this lab.

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Date:

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Copyright 2014 Boston University. All Rights Reserved.

Section One – Variable Length Subnet Masks

2. Imagine that an organization is assigned the address block 169.222.0.0/18, and the

organization needs one subnet with 220 hosts, one subnet with 128 hosts, and one

subnet with 19 hosts.

Create the appropriate network identifiers for each subnet, using the process

established for VLSMs in the overview section. Refer to step 1 for a similar example.

Make sure to show your work.

3. Explain in your own words how the process of allocating subnets using VLSMs differs

from the process of allocating subnets using a fixed length subnet mask.

5. Imagine that an organization is assigned the address block 45.0.0.0/8, and the

organization has an existing subnet with 190 hosts, and another existing subnet with 53

hosts. Further imagine that after the network has been in used for some time, the

organization must add another subnet that requires 105 hosts.

First, use the process established in the overview section to create the network

identifiers for the two existing subnets. Second, use the same process to create the

network identifier for the new subnet (illustrated in step 4). Last, identify the number of

addresses that are left unallocated in the gap between the second and third subnet.

Make sure to show your work.

6. Explain in your own words why allocating a new subnet on an existing network results

in an unavoidable gap of unallocated addresses.

8. Now it is your turn to allocate a new subnet in-between existing subnets on a

network. In the three parts below, keep in mind that there will be a gap of unallocated

addresses in your subnet allocation, similar to the example given in step 7.

a) Imagine that an organization is assigned the address block 222.221.128.0/17, and the

organization has an existing subnet with 107 hosts, and another existing subnet with 51

hosts. Using the process given in the overview section, allocate both subnets and

identify the network identifier for both subnets. Make sure to show your work.

b) Now the organization decides to add an additional subnet that supports 113 hosts.

Allocate this subnet and identify its network identifier, making sure to show your work.

c) Last, the organization decides to add one additional subnet that supports 9 hosts.

Allocate this subnet and identify its network identifier, making sure to show your work.

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9. Explain in your own words how the process of allocating a new subnet in-between

existing subnets works.

 

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Fair Values

$3,000

$25,000

Required:

·       For each of the items, what are possible reasons why no impairment was recorded in 2014 and 2015? (Provide references from the FASB codification.)

·       What considerations will be made to determine if impairment will be recorded in 2016? (Provide references from the FASB codification.)

·       How is anything related to intangibles would appear on the balance sheet and income statement on a comparative basis for 2016, 2015, and 2014?

·       What items will need to be monitored in future years that will continue to impact the carrying value of the intangibles.

 

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Methyl orange is an indicator with a Ka of 10^(-4). Its acid form HIn is red, while its base form In- is yellow.At pH 6.0, the indicator will be (yellow <= correct answer)I don’t understand why this is the correct answer. Here is my understanding, please correct me where I am incorrectWe know that – log Ka = pKa.Therefore, – log (10^(-4)) = 4.Therefore pKa =4.pH = pKa at half-equivalence point, so at half equivalence pt, the pH is four.At equivalence point, we have the same amount of acid and base). Therefore, 2 * half equivalence point = equivalence point. For our problem, 2*4=8, therefore 8 is our equivalence point. So, at a pH of 6, a pH of 6 < a pH of 8, therefore, according to my logic, the indicator would be red because we would not have reached equivalence point yet, and the solution would still be acidic. But my logic is obviously incorrect, so please help me find out where I am wrong. Thanks.

Methyl orange is an indicator with a Ka of 10^(-4). Its acid form HIn is red, while its baseform In- is yellow.At pH 6.0, the indicator will be (yellow &lt;= correct answer)I don’t understand…

 

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Methods of power production, both commonly used and projected. What are some sources of energy and the efficiencies of using them for power production. How do these relate to Thermodynamics? Consider power production in space. What are the effects of generating power on the environment?

 

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