In Drosophila, the allele dp+ determines long wings and dp determines short (“dumpy”) wings. At a separate locus e + determines gray body and e determines ebony bodyy. Both loci are autosomal. The original parents were pure-bred with antagonistic traits, one of the parents had long wings and ebony body. The dihybrid F1 was test crossed with the following results:

Phenotype , Number: (Long, ebony 15) (Long, gray 136) (Short, gray 140) (Short, ebony 145)

You want to determine if the data support whether the genes are linked or sort independently by using the Chi Square test.

a. State the null hypothesis for this experiment.

b. Calculate the X2 value. You must show your work below: 

c. Determine the degrees of freedom and give the p-value range.

d. What does the p-value mean ( In other words, what % of the time you would expect the deviation from expected to occur by chance)?

e. What is your conclusion?

f. What was the genotype of the original parents?

g. Show the inferred chromosomal constitutions of the parents, the F1, the F1 tester, and the progeny. You can do by drawing a pair of parallel lines that represents each chromosome. Indicate the allele or alleles that are on each chromosome above or below the line. If you determined that the genes are linked, then both genes will be on the same chromosome. If they assort independently, then two sets of chromosomes must be drawn, one for each gene.

 

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In Drosophila, brown body is wild type plus dominant to yellow body, and normal wings is wild type plus dominant to vestigial wings. A cross was made between a yellow-bodied male with vestigial wings and a wild-type female. The F1 generation consisted of wild-type males and wild-type females.

a. Define allele symbols for both genes for the moment, assuming that both genes are autosomal.

b. Assuming both genes are autosomal, what is the genotype of the parents and the F1 generations.

The F1 males and females were crossed and the F2 progeny consisted of: 16 yellow-bodied males with vestigial wings ,48 yellow-bodied males with normal wings, 15 brown-bodied males with vestigial wings, 49 wild type males ,31 brown-bodied females with vestigial wings, 97 wild-type females

c. Given this data, determine if body color is autosomal or sex-linked. Support your answer. 

d. Given this data, determine if wing shape is autosomal or sex-linked. Support your answer.

e. Redefine your allele symbols to reflect sex-linkage if necessary and determine the following: Genotype of the female parent: Genotype of the male parent: Genotype of the female F1 Genotype of the male F1

f.Genotypic class of each of the different phenotypes found in the F2: Show work on extra pages if needed yellow-bodied males with vestigial wings yellow-bodied males with normal wings brown-bodied males with vestigial wings wild type males wild-type females 

 

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Solve each of the trigonometric equations exactly over the indicated intervals.

# 1, 5, 9, 13, 17 please.

In Exercises 1-18, solve each of the trigonometric equations exactly over the indicated intervals.cos0 =V20S0 < 2TV2lan2 of gnibrooos (alost22. sin0 = -2,050 < 2TV3(@)nia, = (9)m3. sin0 =V32,0$0 < 2m4. cos0 =2,0 $ 0 < 2mo zobni ovil5.cos0 =,0$0 <2mIN6. sin0 = -,0 $ 0 < 2mowted olens In7. csco = -2, 0 $ 0 < 47orit of (islugibnogjing)8. sec0 = -2, 0 = 0 < 4T79ul2 Cpiphe comi jusdee’ jucLami9.>tan 0 = 0, all real numbers10. cot0 = 0, all real numbersto xabni ovi11. sin(20) = -050 < 2m12. cos(20) = V3,050 < 2Tsigns ovi13.sin=all real numbersUrein calcalatethe solution14. COS= -1, all real numbers15. tan(20) = V3, -27 $ 0 < 2TSubstimeibe16. tan(20) = – V3, all real numbersgas svilostlot orli otel17.sec0 = -2, -2T $0 <018. csco =2V/3step 2 Solve wash4013860 90 03bas niertol zoulev noida

 

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In excel Please, Thanks

 1-A certain convertible bond has a conversion ratio of   40 and a conversion premium of  15 ​%.  The current market price of the underlying common stock is  ​$36 .  What is the​ bond’s conversion​ equivalent?

The​ bond’s conversion equivalent is  $__________________

2-You are considering investing  ​$820 in Higgs B. Technology Inc. You can buy common stock at  ​$27.33 per​ share; this stock pays no dividends. You can also buy a convertible bond​ ($1,000 par​ value) that is currently trading at  ​$820

and has a conversion ratio of  25 .  It pays  ​$48 per year in interest. If you expect the price of the stock to rise to

​$35.93 per share in 1​ year, which instrument should you​ purchase?

3-A certain 6​%  annual coupon rate convertible bond​ (maturing in 20​ years) is convertible at the​ holder’s option into

20 shares of common stock. The bond is currently trading at ​$800 . The stock​ (which pays 72 ​¢ a share in annual​ dividends) is currently priced in the market at ​$30.19 a share.

a. What is the​ bond’s conversion​ price?

b. What is its conversion​ ratio?

c. What is the conversion value of this​ issue? What is its conversion​ parity?

d. What is the conversion​ premium, in dollars and as a​ percentage?

e. What is the​ bond’s payback​ period?

f. If comparably​ rated, nonconvertible bonds sell to yield  8 % comma what is the investment value of the​ convertible?

 

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In examining the 1851 political cartoon ( Document #3 ), how are Southerners arguing against Northern protests of the 1850 Fugitive Slave Act? To what extent does this image relate to the issues raised regarding nullification in Documents #1 and #2? How does the 1856 political cartoon ( Document #4 ) relate to the iss ues arising from the Kansas – Nebraska Act? To what extent did slavery complicate the process and politics of westward expansion in the 1840s and 1850s?  

 

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