If the original distribution of x values is known to be normal, do we need to make any restriction about sample size in order to claim that the distribution of sample means xtaken from random samples of a given size is normal?
If the reaction N2 (g) + 3 H2 (g) –> 2 NH3 (g) has the concentrations 0.1 M for nitrogen, 0.5 M for hydrogen and 0.25 M for ammonia gas, what is the Kc? Show all work. Does this mean that there are more reactants or products at equilibrium? Explain how you determined that.
How do you determine what will happen to a gaseous reaction at equilbrium when the volume is changed (either increased or decreased)? Explain.
Explain what will happen to this reaction at equilibrium if the container is heated up to a higher temperature. 2 SO2 (g) + O2 (g) <-> 2 SO3 (g) + heat
If the only information you were given about Ryan corperation, a large public company in business for many years, was that had a current ratio of 2.9, what could you determine from this? A. you could determine that Ryan has an activity problem because Ryan;s current ratio is greater than 2 which is the rule of thumb for the current ratio B. Nothing, you would also need Ryan Corporation’s current ratios from the last few years of Ryan’s competitorsC. Nothing, you would also need the current ratio from last years S&P 500 indexD. You could determine that Ryan has a liquidity because Ryan’s current ratio is greater than 2 which is the rule of thumb for the current ratio
If the only information you were given about Ryan Corporation, a large public companyin business for many years, was that had a current ratio of 2.9, what could youdetermine from this?A. you…
If the reaction Fe2N (s) + 3/2 H2 (g) -> <- 2Fe(s) + NH3(g) comes to equilibrium at a total pressure of 1 atm, analysis of the gas shows that at 700 K and 800 K pNH3/pH2 = 2.165 and 1.083, respectively, if only H2 was present initially with an excess of Fe2N. Calculate deltaG at 298.15 K.
If the reaction Fe2N (s) + 3/2 H2 (g) -> <- 2Fe(s) + NH3(g) comes to equilibrium at a totalpressure of 1 atm, analysis of the gas shows that at 700 K and 800 K pNH3/pH2 = 2.165 and1.083,…
(Note: Be careful not to round any intermediate steps less than six decimal places.)
If the rate of inflation is 5.9%, what nominal interest rate is necessary for you to earn a 3.7% real interest rate on your investment? (Note: Be careful not to round anyintermediate steps less than six decimal places.) The nominal interest rate is %_ (Round to two decimal places.)
If the rate constant at 20 degrees CELSIUS IS 4.3(10^-5). How long would it take for 83% of the compound to decompose ? if the rate constant is 9.0(10^-4) at 55 degrees Celsius what will the activation energy be?
If the radius of the circle is 11.7 km, what is the area of the circle? Use complete sentences to explain how to solve this. Please.
12,800cm3s
This is a classic Related Rates problems. The idea behind Related Rates is that you have a geometric model that doesn’t change, even as the numbers do change.
For example, this shape will remain a sphere even as it changes size. The relationship between a where’s volume and it’s radius is
##V=4/3pir^3##
As long as this geometric relationship doesn’t change as the sphere grows, then we can derive this relationship implicitly, and find a new relationship between the rates of change.
is where we derive every variable in the formula, and in this case, we derive the formula with respect to time.
So we take the derivative of our sphere:
##V=4/3pir^3##
##(dV)/(dt)=4/3pi(3r^2)(dr)/dt##
##(dV)/(dt)=4pir^2(dr)/dt##
We were actually given ##(dr)/(dt)##. It’s ##4(cm)/s##.
We are interested in the moment when the diameter is 80 cm, which is when the radius will be 40 cm.
The rate of increase of the volume is ##(dV)/(dt)##, which is what we are looking for, so:
##(dV)/(dt)=4pir^2(dr)/dt##
##(dV)/(dt)=4pi(40cm)^2(4(cm)/s)##
##(dV)/(dt)=4pi(1600cm^2)(4(cm)/s)##
##(dV)/(dt)=4pi(1600cm^2)(4(cm)/s)##
##(dV)/(dt)=12,800(cm^3)/s##
And the units even work out correctly, since we should get a volume divided by time.
Hope this helps.
If the probability that an event will occur is two elevenths 2/11, then the probability that the event will not occur is nine elevenths 9/11, and the odds in favor of the event occurring are ________.
If the probability of an injury is 0.19, the cost of the injury is $13897, the insurer’s loading costs are $4853, and the number of policies is 383, then in a competitive insurance market, each policy will cost $____.
** Show work please
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