1.If the multiplier for government spending is 1.60 and government spending is increased by ​$160

​billion, calculate the amount by which the demand curve will ultimately shift.

Shift of the demand curve​ =

​$nothing

billion. ​(Enter your response as an integer and include a minus sign if​ necessary.)

2. Debit Cards as a Fiscal Stimulus. Here is one unusual fiscal​ policy: The government would issue​ time-dated debit cards to each person that had to be spent on goods and services produced only by U.S. firms within a fixed period​ (say, three​ months) or become worthless. Suppose the government was considering whether to issue​ $400 in​ time-dated debit cards to each household or give each household​ $400 in cash instead.

Suppose a family had large credit card​ debt, which it wished to reduce. Of the two​ plans, the family would prefer

A.

the cash payments​ program, since cash could be used to pay off some of the credit card debt.

B.

the debit card​ program, since they did not need to use cash to buy goods and services.

C.

​neither, since the credit card was fixed and was dependent on the interest rate.

D.

both of them​ equally, since they involved payments of equal size.

3. Looking Backwards. Some critics of stabilization policy say that policymakers are always looking

backwards long dash through a rear view mirror at past data long dash and

thus cannot conduct stabilization policy.

Which of the following is a defense for​ policymakers?

A.

​Recently, the recognition of lags in data collection has eliminated the use of stabilization policies.

B.

Economic forecasts using past data are better than forecasts using current data.

C.

Sometimes economic conditions require that stabilization policies be enacted by relying on the best available data.

D.

​Recently, analysts have found that future trends usually follow past data.

4. The largest component of federal spending is

▼

discretionary spending

consumption spending

deficit spending

entitlement spending

.

5. Which of the following is an entitlement​ program?

A.

Medicare spending

.

B.

Corporate income taxes

.

C.

Government investment spending

.

D.

Personal consumption expenditure

6. Automatic Stabilizers and Fluctuations in Output. Because of automatic​ stabilizers, the states that have a more generous unemployment insurance program experience

▼

smaller

no

larger

fluctuations in output.

7. Annual government spending not stipulated by existing laws is called

A.

inflationary.

B.

entitlement.

C.

mandatory.

D.

discretionary.

8. Based on the​ Laffer’s theory why do lower tax rates increase government​ revenue?

A.

Companies will hire fewer workers when taxes are lower.

B.

Workers will be willing to work less when taxes are lower.

C.

Workers will think it is unfair when the government taxes them less.

D.

When workers get to keep more of their​ salary, they will work harder thus increasing the tax base

9. Long-run average income is known as

▼

permanent income

national income

disposable income

.

10. What was the effect on the economy from the Kennedy and Johnson tax​ cuts?

A.

Real GDP and consumption grew at rates of​ 4% each year between 1963 and 1966.

B.

Real GDP and consumption were unchanged from what they would have been.

C.

Real GDP and consumption declined each year between 1963 and 1966.

D.

Real GDP and consumption were unchanged entirely.

 

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If the price needs to be adjusted, what’s the lowest the product could be offered and still have a positive NPV (keeping all other assumptions the same)

Marketing study                     $100,000

New PDA cost                                    $200,000

Fixed Cost                             $2.1 million

Estimated sales per year:

Year 1 – $75,000

Year 2 – $85,000

Year 3 – $80,000

Year 4 – $70,000

Year 5 – $65,000

Unit price of new product     $240

Equipment                              $10.5 million

Value of equipment in 5 years – $1.1 million

Networking Capital               22%  No initial outlay for NWC

Corporate tax                        30%

Required return                      10%

 

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5.

If the particle in question #4 had a charge of 1.0 C and was moving with a speed of 1.0 m/s, what is the magnitude of magnetic force acting on it caused by a B-field with a magnitude of 0.5 T.

a. 0.90 N  

b. 0.53 N 

c. 0.59 N 

d. 0.17 N  

6.

Identify the smallest scale at which one can show magnetic effects? 

a. A macroscopic object such as an iron nail 

b. A section of a bar magnet 

c. A magnetic monopole 

d. An atom of an element such as iron

7.

JJ Thomson’s experiment observing the motion of a beam of electrons in crossed E and B fields allowed the measurement of which of the following? 

a. The electron charge 

b. The charge to mass ratio for an electron 

c. The charge of the electron 

d. The magnetic field surrounding an electron

8.

A proton is moving (along the +x axis) through crossed E and B fields undeflected. The speed is 2.6×107 m/s. The E-field has a magnitude of 1.9×104 N/C and is directed along the negative y axis. Determine the magnitude of the B-field.

a. 7.3×10-4 T  

b. 3.1×10-4 T 

c. 9.8×10-4 T 

d. 5.2×10-4 T

 

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 If the p-value is less than or equal to 0.05, it means that

1. Evidence supports the null hypothesis
2. There is evidence to reject the null hypothesis
3. There is very strong evidence to accept the null hypothesis
4. There is very strong evidence to reject the null hypothesis

 

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 Recursive and methodsRecursive productOfEvens(),,, Recursive Sum of Array Elements，，Recursive Selection Sort，，Recursive countDigitMatches()，，Recursive generatePattern()

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If The outer Loop iterates once For Each Element in theI’ array . The startscan Variable marks the position whereI’ the scan should begin .For ( startscan = O ; startscan (array . length – 1 1 ; startScant + !)If Assume the First element in the scannable areaIT is the smallest value .min Index = Startscan ;"min Value = array [ startscan ] ;I’d Scan the array , starting at the and Element inIf the scannable area . We are looking For the smallest*I’l value in the scannable area .`For lindex = startscan + 1 ; index < array . Length ; index + + |if (array [ index ! < minvalue !minValue = array [ index ] ;mini Index = index;`I’M Swap the Element with the smallest valueI’M with the First Element in the scannable area .array [ min Index ] = array [ startscan ] :`array [ startScan ! = minvalue ;"

 

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