How Do I Find The Real Zeros Of A Polynomial Function On A Graphing Calculator

If you are using a TI-83 or TI-84, then you first graph the function by going into Y= and entering the part after the f(x) or y= after Y1.

Now you just need to hit the “graph” key, and you should see a nice graph laid out there.

Now what you are looking for are the zeroes. These are the points where the graph intersects the ##x##-axis, like shown in the picture below:

If you cannot see them, then you may need to adjust your window. You can do this by pressing the “Window” key and adjusting the x-max and min to whatever you need.

Now you will need to find those intercepts. You can do this by hitting 2nd -> Calc (normally the “Trace” button) -> Zero. Once you have done this, the calculator will ask you to specify the left bound of the zero. To do this, move the cursor using the arrow keys (or enter an x-value in directly using the number keys) so that it is somewhere close to the left of where the function crosses the x-axis. Press ENTER.

Then, specify the right bound in the same way, except you want the cursor to be to the right of the crossing point.

Lastly, it will ask you to guess where the zero is. You can help the calculator find the zero by moving the cursor close to the crossing point. Then, the calculator will report the zero, which will be the x-value. If there are other real zeros, you can find them using this method.

In addition, whenever you find a zero your calculator automatically stores it as your “X” value. Therefore if you want to use that zero value for something else (plugging it into another equation, etc), then you can do that by just using the “X” key (next to Alpha) wherever you want that value.

Here is a video that might help you as well:

 
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How Do I Find The Partial Sum Of An Arithmetic Sequence

The partial sum of an arithmetic sequence can be found using the formula ##S=n/2(a1+an)## where n= the number of terms, a1= the value of the first term, and an= the value of the last (nth) term.

As an example, if you were to find the partial sum of the sequence 1, 3, 5, 7, 9, …, 49, you would first need to determine that there are 25 terms, a1= 1 and an=49. ##25/2(1+49) = 625##.

Another example might ask you to find the sum of the first 20 terms of the sequence 8, 13, 18, 23, … To find an, you could use the formula ##an=dn+a0## where d= the common difference and a0 = the 0th term, or the term before the first term in the sequence. So ##an=5*20+3 = 103##. Therefore ##S=20/2(8+103) = 1110##.

Here’s a video from my YouTube channel (www.YouTube.com/MrDaveEbert) with another example:

 
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How Do I Find The Npv Using The Required Rate Of Return When There Are No Given

My professor gave us the NPV answer as $9,930.22 I think. But I need to know how to get there considering she doesn’t even teach the material. Please help. Thank you.

How do I find the NPV using the required rate of return when there are no given cash flows? 3 year expansion project. initial fixed investment of $2.7 million. Depreciates straight line tozero…

 
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How Do I Find The Magnitude And Direction Angle Of The Vector V 6i 6j

Magnitude = ##|6i-6j|=sqrt(6^2+(-6)^2)=sqrt(72)=6sqrt(2)”##Angle = ##arctan(-6/6)=arctan(-1)=-pi/4=-45°##

If you draw this vector on the plane, the x-y coordinate axis, as (6,-6) because ##i## is the unit vector in the x-direction and ##j## in the y-direction. Then pictorially it might seem easier.

So if you draw the vector (so join the line between the point (6,-6) and the origin), and draw the perpendicular line between the point and the x-axis. Now, you should see a triangle, more specifically a right-angles triangle.

Now that you have you’re right-angles triangle you can use Pythagoras to find the magnitude of the vector (length of the straight line between the origin and the point (6,-6)) and the use SOHCAHTOA to find the angle between the x-axis and the vector (be careful, here if the vector is the on the left-hand side of the plane i.e. the x-coordinate is negative, then you will have to make sure the you take the angle from the positive side of the x-axis, so do ##pi/2(1-theta)##.

Some quick formulae that may be helpful to do quick calculation:magnitude of ##ai+bj=|ai+bj|=sqrt(a^2+b^2)####theta=arctan(b/a)##if ##b<0## then angle of ##ai+bj=pi/2(1-theta)##if ##bge0## then angle of ##ai+bj=theta##

 
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How Do I Find The Foci Of An Ellipse If Its Equation Is X 2 36 Y 2 64 1

##x^2/36+y^2/64=1##

##a^2=64####b^2=36##

The center is ##(0,0)##.

The y-axis is the major axis. We know this because the ##y^2## term has the larger denominator.

We find the foci using the following equation and solving for ##c##.

##c^2=a^2-b^2####c^2=64-36####c^2=28####c=sqrt(2*2*7)####c=2sqrt(7)##

The coordinates for the foci are ##(0,+-c) -> (0,+-2sqrt(7))##

 
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How Do I Journalize These Transactions

How do I journalize these transactions?Journalizing stockholders equity transactions. Airborne Manufacturing Co. complete the following transactions during 2009Jan 16- Declared a cash dividend on the 4%, $102 par preferred stock (1,050 shares outstanding) Declared a $0.55 per share dividend on the 95,000 shares of common stock outstanding. The date of record is January 31, and the payment due date is February 15.Feb15- Paid the cash dividendsJune 10 Split common stock 2 for 1. Before the split, airborne had 95,000 shares of $10 par common stock outstandingJul 30 Distributed a 25% stock dividend on the common stock. The market value of the common stock was $10 per share

 
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How Do I Find The Dot Product Of 1 I 2 3i And 2 I 3 2i

how do I find the dot product of (1 – i , 2+3i) and (2 + i, 3 – 2i) ?

I know there is something with conjugates of a2, and b2 (I bolded them) I get 1 + 10 i and the book says 6 +21i… this doesn’t match….

 
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How Do I Incorporate A Selective Statement In The Code Below

How do I incorporate a selective statement in the code below?

Clarification

  1. Demonstrate your understanding of GUI.
  2. Use selection and repetition statements in this program.

import java.text.DecimalFormat;

import javax.swing.JOptionPane;

public class module3case {

   public static void main(String[] args) {

      String choice = null;

      do {

         DecimalFormat formatter = new DecimalFormat(“#,##0.00”);

         double propertyTaxRate;

         double actualValue;

         double assessmentValue;

         double tax;

         actualValue = Double.valueOf(JOptionPane.showInputDialog(“What is the value of your property?”));

         propertyTaxRate = Double.valueOf(JOptionPane.showInputDialog(“What is the property tax of the locality?”));

         tax = actualValue * propertyTaxRate/100;

         assessmentValue = actualValue +tax;

         JOptionPane.showMessageDialog(null, “Your assessment value is $”

                + formatter.format(assessmentValue)+”n”

                +”The local real estate property tax rate: “+propertyTaxRate+”n”

                + “Property tax based on the assessment is $”

                + formatter.format(tax) + “.”);

         choice =JOptionPane.showInputDialog(“Press E to terminate the program “);

         }while(!”E”.equalsIgnoreCase(choice));

   }

}

 
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How Do I Find The Directrix Of The Parabola Y 2x 2

To find the directrix of a parabola wohse equation is ##y=ax^2+bx+c## you can use this formula:##y= (-1-(b^2-4ac))/(4a)##So in case of this parbola ##y=2x^2##the directrix is##y=(-1-(0^2-4*2*0))/(4*2)####y=-(1)/(8)##

 
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How Do I Trace The Path A Mature Sperm Must Make Upon Entering The Seminiferous

How do I trace the path a mature sperm must make upon entering the seminiferous tubule lumen to expulsion from the body and identify accessory glands and their secretions that contribute to the final product, semin?

* Path frawelled by mature sperm .Seminiferous tubcoles. Refe testis- Vasa efferentiaEjaculatoryDuct of seminalvesicledirectDuctusProstate glanddeferensEpididymis( vas deferens )…

 
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