How Do I Find The X Intercepts Of The Graph Of Y X 2 11x 18

/in /by

To find the x-intercepts of the graph of ##y=x^2-11x+18## substitute 0 for y and solve for x.

##0=x^2-11x+18##

Now, factor the quadratic expression on the right.

##0=(x-2)(x-9)##

and set each factor equal to 0 and solve.

##(x-2)=0## or ##(x-9)=0## ##=>x=2## or ##x=9##

The x-intercepts of any function ##y = f(x)## are found

by setting ##f(x)=0## since the y-coordinate of any point on the

x-axis is zero.

See image below.

 
"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"
ORDER NOW

How Do I Find The Water Insoluble Fraction Fert And Water Soluble Fraction Fert

/in /by

How do I find the water insoluble fraction (% fert) and water soluble fraction (%fert.) for Trikote; polymer/sulfur coated urea

39-0-0 SGN 175 which has a water insoluble fert. mass of 4.01 grams and a reference salt index(per unit N applied) of 0.05.

 
"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"
ORDER NOW

How Do I Find The Value Of Log 100

/in /by

First, you must rewrite this in exponential form.

log is the inverse of exponential. You must rewrite it in that form to figure it out without a calculator. First, figure out your base, the subscript to log. In this case, it is not specified, so the general base is ten. The x value you were trying to find is now the exponent to your base and in this case ##10^x=100## . You know through common sense that ##10^2## =100 so x=2. Therefore, the ##log100## = 2

 
"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"
ORDER NOW

How Do I Find The Sine Of The Angle Between Two Vectors

/in /by

I’m assuming you either have the components of the vectors, or their magnitude and angle. You will need to apply the cross product to get the sine.

Honestly, it’d be much easier if someone explains it to you on paper, it’s too long to type here and may seem hard, but it’s pretty easy.

Let’s assume the vectors are U and V.

U X V (cross product) = |U| * |V| * Sin(theta)

Which is the magnitude of the first vector, multiplied by the magnitude of the second vector, multiplied by the sine of the angle between them.

Now, you have the magnitude of both vectors, but lack the sine and the actual cross product.

To get the cross product, apply this:

Replace a with U and b with V.

Doing this will get you the components, you want the magnitude, I assume you know it, but anyway, the magnitude is ##sqrt(x i^2 +yj 2 + zk ^2)## It’s the square root of all the components squared.

Replace in the original law, and solve for sine.

 
"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"
ORDER NOW

How Do I Find The Real Zeros Of A Polynomial Function On A Graphing Calculator

/in /by

If you are using a TI-83 or TI-84, then you first graph the function by going into Y= and entering the part after the f(x) or y= after Y1.

Now you just need to hit the “graph” key, and you should see a nice graph laid out there.

Now what you are looking for are the zeroes. These are the points where the graph intersects the ##x##-axis, like shown in the picture below:

If you cannot see them, then you may need to adjust your window. You can do this by pressing the “Window” key and adjusting the x-max and min to whatever you need.

Now you will need to find those intercepts. You can do this by hitting 2nd -> Calc (normally the “Trace” button) -> Zero. Once you have done this, the calculator will ask you to specify the left bound of the zero. To do this, move the cursor using the arrow keys (or enter an x-value in directly using the number keys) so that it is somewhere close to the left of where the function crosses the x-axis. Press ENTER.

Then, specify the right bound in the same way, except you want the cursor to be to the right of the crossing point.

Lastly, it will ask you to guess where the zero is. You can help the calculator find the zero by moving the cursor close to the crossing point. Then, the calculator will report the zero, which will be the x-value. If there are other real zeros, you can find them using this method.

In addition, whenever you find a zero your calculator automatically stores it as your “X” value. Therefore if you want to use that zero value for something else (plugging it into another equation, etc), then you can do that by just using the “X” key (next to Alpha) wherever you want that value.

Here is a video that might help you as well:

 
"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"
ORDER NOW

How Do I Find The Partial Sum Of An Arithmetic Sequence

/in /by

The partial sum of an arithmetic sequence can be found using the formula ##S=n/2(a1+an)## where n= the number of terms, a1= the value of the first term, and an= the value of the last (nth) term.

As an example, if you were to find the partial sum of the sequence 1, 3, 5, 7, 9, …, 49, you would first need to determine that there are 25 terms, a1= 1 and an=49. ##25/2(1+49) = 625##.

Another example might ask you to find the sum of the first 20 terms of the sequence 8, 13, 18, 23, … To find an, you could use the formula ##an=dn+a0## where d= the common difference and a0 = the 0th term, or the term before the first term in the sequence. So ##an=5*20+3 = 103##. Therefore ##S=20/2(8+103) = 1110##.

Here’s a video from my YouTube channel (www.YouTube.com/MrDaveEbert) with another example:

 
"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"
ORDER NOW

How Do I Find The Npv Using The Required Rate Of Return When There Are No Given

/in /by

My professor gave us the NPV answer as $9,930.22 I think. But I need to know how to get there considering she doesn’t even teach the material. Please help. Thank you.

How do I find the NPV using the required rate of return when there are no given cash flows? 3 year expansion project. initial fixed investment of $2.7 million. Depreciates straight line tozero…

 
"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"
ORDER NOW

How Do I Find The Magnitude And Direction Angle Of The Vector V 6i 6j

/in /by

Magnitude = ##|6i-6j|=sqrt(6^2+(-6)^2)=sqrt(72)=6sqrt(2)”##Angle = ##arctan(-6/6)=arctan(-1)=-pi/4=-45°##

If you draw this vector on the plane, the x-y coordinate axis, as (6,-6) because ##i## is the unit vector in the x-direction and ##j## in the y-direction. Then pictorially it might seem easier.

So if you draw the vector (so join the line between the point (6,-6) and the origin), and draw the perpendicular line between the point and the x-axis. Now, you should see a triangle, more specifically a right-angles triangle.

Now that you have you’re right-angles triangle you can use Pythagoras to find the magnitude of the vector (length of the straight line between the origin and the point (6,-6)) and the use SOHCAHTOA to find the angle between the x-axis and the vector (be careful, here if the vector is the on the left-hand side of the plane i.e. the x-coordinate is negative, then you will have to make sure the you take the angle from the positive side of the x-axis, so do ##pi/2(1-theta)##.

Some quick formulae that may be helpful to do quick calculation:magnitude of ##ai+bj=|ai+bj|=sqrt(a^2+b^2)####theta=arctan(b/a)##if ##b<0## then angle of ##ai+bj=pi/2(1-theta)##if ##bge0## then angle of ##ai+bj=theta##

 
"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"
ORDER NOW

How Do I Find The Foci Of An Ellipse If Its Equation Is X 2 36 Y 2 64 1

/in /by

##x^2/36+y^2/64=1##

##a^2=64####b^2=36##

The center is ##(0,0)##.

The y-axis is the major axis. We know this because the ##y^2## term has the larger denominator.

We find the foci using the following equation and solving for ##c##.

##c^2=a^2-b^2####c^2=64-36####c^2=28####c=sqrt(2*2*7)####c=2sqrt(7)##

The coordinates for the foci are ##(0,+-c) -> (0,+-2sqrt(7))##

 
"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"
ORDER NOW

How Do I Journalize These Transactions

/in /by

How do I journalize these transactions?Journalizing stockholders equity transactions. Airborne Manufacturing Co. complete the following transactions during 2009Jan 16- Declared a cash dividend on the 4%, $102 par preferred stock (1,050 shares outstanding) Declared a $0.55 per share dividend on the 95,000 shares of common stock outstanding. The date of record is January 31, and the payment due date is February 15.Feb15- Paid the cash dividendsJune 10 Split common stock 2 for 1. Before the split, airborne had 95,000 shares of $10 par common stock outstandingJul 30 Distributed a 25% stock dividend on the common stock. The market value of the common stock was $10 per share

 
"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"
ORDER NOW