12,800cm3s
This is a classic Related Rates problems. The idea behind Related Rates is that you have a geometric model that doesn’t change, even as the numbers do change.
For example, this shape will remain a sphere even as it changes size. The relationship between a where’s volume and it’s radius is
##V=4/3pir^3##
As long as this geometric relationship doesn’t change as the sphere grows, then we can derive this relationship implicitly, and find a new relationship between the rates of change.
is where we derive every variable in the formula, and in this case, we derive the formula with respect to time.
So we take the derivative of our sphere:
##V=4/3pir^3##
##(dV)/(dt)=4/3pi(3r^2)(dr)/dt##
##(dV)/(dt)=4pir^2(dr)/dt##
We were actually given ##(dr)/(dt)##. It’s ##4(cm)/s##.
We are interested in the moment when the diameter is 80 cm, which is when the radius will be 40 cm.
The rate of increase of the volume is ##(dV)/(dt)##, which is what we are looking for, so:
##(dV)/(dt)=4pir^2(dr)/dt##
##(dV)/(dt)=4pi(40cm)^2(4(cm)/s)##
##(dV)/(dt)=4pi(1600cm^2)(4(cm)/s)##
##(dV)/(dt)=4pi(1600cm^2)(4(cm)/s)##
##(dV)/(dt)=12,800(cm^3)/s##
And the units even work out correctly, since we should get a volume divided by time.
Hope this helps.
"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"
If The Particle In Question 4 Had A Charge Of 1 0 C And Was Moving With A Speed
/in Uncategorized /by developer5.
If the particle in question #4 had a charge of 1.0 C and was moving with a speed of 1.0 m/s, what is the magnitude of magnetic force acting on it caused by a B-field with a magnitude of 0.5 T.
a. 0.90 N
b. 0.53 N
c. 0.59 N
d. 0.17 N
6.
Identify the smallest scale at which one can show magnetic effects?
a. A macroscopic object such as an iron nail
b. A section of a bar magnet
c. A magnetic monopole
d. An atom of an element such as iron
7.
JJ Thomson’s experiment observing the motion of a beam of electrons in crossed E and B fields allowed the measurement of which of the following?
a. The electron charge
b. The charge to mass ratio for an electron
c. The charge of the electron
d. The magnetic field surrounding an electron
8.
A proton is moving (along the +x axis) through crossed E and B fields undeflected. The speed is 2.6×107 m/s. The E-field has a magnitude of 1.9×104 N/C and is directed along the negative y axis. Determine the magnitude of the B-field.
a. 7.3×10-4 T
b. 3.1×10-4 T
c. 9.8×10-4 T
d. 5.2×10-4 T
"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"
If The Population Standard Deviation For The Average Loss Was 16 Tons Per Acre D
/in Uncategorized /by developerIf the population standard deviation for the average loss was 16 tons per acre, determine the margin of error for estimating the mean loss per acre for a confidence level of 95% for sample sizes of farmers ranging from 289, 324 and 361. What would be your recommendation to the local Farm Bureau for estimating the average loss of production per acre, given the data you have at hand?
"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"
If The Price Needs To Be Adjusted What S The Lowest The Product Could Be Offered
/in Uncategorized /by developerIf the price needs to be adjusted, what’s the lowest the product could be offered and still have a positive NPV (keeping all other assumptions the same)
Marketing study $100,000
New PDA cost $200,000
Fixed Cost $2.1 million
Estimated sales per year:
Year 1 – $75,000
Year 2 – $85,000
Year 3 – $80,000
Year 4 – $70,000
Year 5 – $65,000
Unit price of new product $240
Equipment $10.5 million
Value of equipment in 5 years – $1.1 million
Networking Capital 22% No initial outlay for NWC
Corporate tax 30%
Required return 10%
"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"
If The Price Of Computers Decreases Then The Sales Of A Substitute Such As A Tel
/in Uncategorized /by developerIf the price of computers decreases, then the:
sales of a substitute, such as a telephone, decrease.
sales of a substitute, such as a telephone, increase.
inventory of computers increases.
inventory of computer software increases.
"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"
If The Probability Distribution For The Random Variable Xis Given In The Table W
/in Uncategorized /by developerXX
If the probability distribution for the random variable Xis given in thetable, what is the expected value of X? Show work. Xi 730 10 20 60p,- 0.40 0.30 0.20 0.10 Enter answer — with its sign — rounded to nearest hundredth (2 placesafter decimal)
"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"
If The Probability Of An Injury Is 0
/in Uncategorized /by developerIf the probability of an injury is 0.19, the cost of the injury is $13897, the insurer’s loading costs are $4853, and the number of policies is 383, then in a competitive insurance market, each policy will cost $____.
** Show work please
"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"
If The Probability That An Event Will Occur Is Two Elevenths 2 11 Then The Proba
/in Uncategorized /by developerIf the probability that an event will occur is two elevenths 2/11, then the probability that the event will not occur is nine elevenths 9/11, and the odds in favor of the event occurring are ________.
"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"
If The Radius Of A Sphere Is Increasing At A Rate Of 4 Cm Per Second How Fast Is
/in Uncategorized /by developer12,800cm3s
This is a classic Related Rates problems. The idea behind Related Rates is that you have a geometric model that doesn’t change, even as the numbers do change.
For example, this shape will remain a sphere even as it changes size. The relationship between a where’s volume and it’s radius is
##V=4/3pir^3##
As long as this geometric relationship doesn’t change as the sphere grows, then we can derive this relationship implicitly, and find a new relationship between the rates of change.
is where we derive every variable in the formula, and in this case, we derive the formula with respect to time.
So we take the derivative of our sphere:
##V=4/3pir^3##
##(dV)/(dt)=4/3pi(3r^2)(dr)/dt##
##(dV)/(dt)=4pir^2(dr)/dt##
We were actually given ##(dr)/(dt)##. It’s ##4(cm)/s##.
We are interested in the moment when the diameter is 80 cm, which is when the radius will be 40 cm.
The rate of increase of the volume is ##(dV)/(dt)##, which is what we are looking for, so:
##(dV)/(dt)=4pir^2(dr)/dt##
##(dV)/(dt)=4pi(40cm)^2(4(cm)/s)##
##(dV)/(dt)=4pi(1600cm^2)(4(cm)/s)##
##(dV)/(dt)=4pi(1600cm^2)(4(cm)/s)##
##(dV)/(dt)=12,800(cm^3)/s##
And the units even work out correctly, since we should get a volume divided by time.
Hope this helps.
"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"
If The Radius Of The Circle Is 11 7 Km What Is The Area Of The Circle Use Comple
/in Uncategorized /by developerIf the radius of the circle is 11.7 km, what is the area of the circle? Use complete sentences to explain how to solve this. Please.
"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"
If The Rate Constant At 20 Degrees Celsius Is 4 3 10 5 How Long Would It Take F
/in Uncategorized /by developerIf the rate constant at 20 degrees CELSIUS IS 4.3(10^-5). How long would it take for 83% of the compound to decompose ? if the rate constant is 9.0(10^-4) at 55 degrees Celsius what will the activation energy be?
"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"