f(x) = x2+lnx. What is f'(5)?

Please help. I’m very confused.

Given function isf (x) = x2 + ln x.Thenf 0 (x) When x = 5f 0 (5) = [2 × 5] + d(f (x))dxd 2=(x + ln x)dxdd 2(x ) +(ln x)=dxdx1= 2×2−1 +x1= 2x + .x= 1150 + 151= 10 + =…

 

"Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!"